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What is the empirical formula of a compound composed of 35.9 g of potassium (K) and 7.35 g of oxygen (O)?

Insert subscripts as needed in the empirical formula: KO

Answer :

Final answer:

The empirical formula of a compound composed of 35.9 g of potassium (K) and 7.35 g of oxygen (O) is K2O. This is obtained by calculating the ratio of moles for each element, and then expressing this ratio in the simplest form as subscripts.

Explanation:

The empirical formula of a compound refers to the simplest ratio of elements present in the compound. In this case, we have potassium (K) and oxygen (O) in the compound. To find the empirical formula:

  1. Determine the number of moles for each element. Using the atomic masses of potassium (K = 39.1 g/mol) and oxygen (O = 16.0 g/mol), we have 35.9 g ÷ 39.1 g/mol ≈ 0.92 moles of K and 7.35 g ÷ 16.0 g/mol ≈ 0.46 moles of O.
  2. Calculate the simplest ratio of the moles by dividing each value by the smallest number of moles calculated in the previous step, 0.46. Hence, we have 0.92/0.46 ≈ 2 and 0.46/0.46 = 1.
  3. Write out the empirical formula using these numbers as subscripts. The empirical formula is therefore K2O.

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