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A man with a mass of 80 kg is standing in a lift, which is accelerating upwards with an acceleration of [tex]0.6 \, \text{m/s}^2[/tex]. What is the magnitude of the force between the man and the lift floor?

a. 480 N
b. 48 N
c. 128 N
d. 800 N

Answer :

Final answer:

The total force between the man and the lift floor is 832 N when accounting for both his weight and the additional force from the lift's upward acceleration, but the provided options do not include this correct value. The closest approximation among the options is 800 N.

Explanation:

When considering the force between the man and the lift floor while the lift is accelerating upwards, we must take into account both the weight of the man and the additional force from the acceleration. The man's weight is the product of his mass and gravity (Fweight = mg), which is 80 kg × 9.8 m/s2 = 784 N. To find the additional force due to acceleration, we use Facceleration = ma, which is 80 kg × 0.6 m/s2 = 48 N. Adding these two forces together gives us the total force exerted on the floor by the man, which is 784 N + 48 N = 832 N. Therefore, the correct answer is not listed among the options provided, but the closest correct answer to the size of the force between the man and the lift floor is:

d. 800 N (approximated)

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