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Answer :
Answer:
F' = 251.2 lb
Explanation:
It is given that,
The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car’s speed and inversely as the radius of the curve. So,
[tex]F=\dfrac{kWv^2}{r}[/tex]
W is the weight
v is the speed
r is the radius of curve
W is constant, So
[tex]F=\dfrac{kv^2}{r}[/tex]
If F = 126 lb, v = 25 mph and r = 400 ft
F' = ?, v' = 45 mph and r' = 650 ft
[tex]\dfrac{F}{F'}=(\dfrac{v}{v'})^2\times (\dfrac{r'}{r})[/tex]
[tex]\dfrac{126}{F'}=(\dfrac{25}{45})^2\times (\dfrac{650}{400})[/tex]
On solving above equation,
F' = 251.2 lb
So, 251.2 lb of force would keep the same car going 45 mph from skidding on a curve of radius 650 ft. Hence, this is the required solution.
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