Answer :

Final answer:

The mass in grams of 1.73 moles of Calcium Hydride (CaH₂) is approximately 72.5g. This is calculated by first determining the molar mass of CaH₂ (42.10 g/mol) and then multiplying this by the given number of moles.

Explanation:

The question is asking about the calculation of mass of 1.73 moles of Calcium Hydride (CaH₂). The first step in answering this question is to find the molar mass of Calcium Hydride. In the Periodic Table, the molar mass of Calcium (Ca) is approximately 40.08 g/mol and that of Hydrogen (H) is approximately 1.01 g/mol. Since there are two atoms of Hydrogen in Calcium Hydride, the total molar mass becomes that of Calcium plus 2 times that of Hydrogen. Therefore, the molar mass of CaH₂ is 40.08 g/mol (for Ca) + 2*1.01 g/mol (for H) which totals to 42.10 g/mol.

Next, we multiply the number of moles by the molar mass to find the mass: 1.73 moles * 42.10 g/mol = ~72.8 g. Therefore, the mass in grams of 1.73 mol of CaH₂ is approximately 72.8g, which is closest to the answer choice b. 72.5g.

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