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The velocity of the bee between 4.00 s and 8.00 s can be determined from the position vs. time graph by finding the slope of the line during this time interval. This is calculated by dividing the change in position by the change in time.
The velocity of an object, in this case, a bee, can be determined from a position vs. time graph by finding the slope of the line during the given time interval. The slope is calculated as the change in position (vertical axis) divided by the change in time (horizontal axis), or 'rise over run'.
For the bee between 4.00 s and 8.00 s, you will need to identify the position of the bee at these two points on the graph and use these values in the slope formula. For instance, if at 4.00 s the bee's position is 50 m, and at 8.00 s it's at 100 m, the change in position is (100 m - 50 m) = 50 m. The change in time is (8.00 s - 4.00 s) = 4.00 s. Therefore, using the velocity definition, Velocity = Change in position / Change in time = 50 m / 4.00 s = 12.5 m/s. Thus, during this time interval, the bee is moving at a velocity of 12.5 m/s.
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Rewritten by : Barada
Answer:
v = 2 m/s.
Explanation:
From the given graph, it is clear that the position is bee is 8 m between 4 s to 6 s. It would mean that its displacement is equal to 0 because final position is equal to initial position.
Between 6 s to 8 s, its velocity is decreasing and it is calculated using slope. The slope of position time graph gives velocity of an object.
[tex]\text{slope}=v=\dfrac{8-4}{8-6}\\\\v=\dfrac{4\ m}{2\ s}\\\\v=2\ m/s[/tex]
So, the velocity of the bee between 4 s to 8 s is 2 m/s.
