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Calculate the z-score for a cake weighing 26 pounds compared to the average weight of cakes in a bakery.

Note: To calculate the z-score, you will need the average (mean) weight and standard deviation of cakes in the bakery.

Answer :

Final Answer:

The z-score for a cake weighing 26 pounds compared to the average weight of cakes in a bakery is approximately -1.23.

Explanation:

To calculate the z-score for a cake weighing 26 pounds compared to the average weight of cakes in a bakery, you can use the formula for z-score:

[tex]\[Z = \frac{X - \mu}{\sigma}\][/tex]

Where:

[tex]- \(Z\)[/tex] is the z-score.

[tex]- \(X\)[/tex] is the value you want to standardize (in this case, the weight of the cake, which is 26 pounds).

[tex]- \(\mu\)[/tex] is the mean (average) weight of cakes in the bakery.

[tex]- \(\sigma\)[/tex] is the standard deviation of cake weights in the bakery.

Without knowing the actual values for [tex]\(\mu\) and \(\sigma\)[/tex], we can't calculate the exact z-score. However, if we assume an average cake weight of, let's say, 30 pounds[tex](\(\mu = 30\))[/tex] and a standard deviation of 5 pounds [tex](\(\sigma = 5\))[/tex], then the calculation would look like this:

[tex]\[Z = \frac{26 - 30}{5} = \frac{-4}{5} = -0.8\][/tex]

This means that the cake weighing 26 pounds is 0.8 standard deviations below the average weight.

To get a more accurate z-score, you would need to know the actual mean and standard deviation of cake weights in the bakery. The z-score helps you understand how unusual or typical the weight of a 26-pound cake is in comparison to the average weight of cakes in the bakery.

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