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Answer :
Final answer:
The water absorbed 2043.7 calories of heat.
Explanation:
In this question, we are given the mass of water and the change in temperature of the water. We need to calculate the amount of heat absorbed by the water. The specific heat capacity of water is 1 calorie/gram * °C. To calculate the heat absorbed, we can use the formula q = m * C * ΔT, where q is the heat absorbed, m is the mass of water, C is the specific heat capacity of water, and ΔT is the change in temperature of the water.
Plugging in the given values, we get q = 153.7 g * 1 calorie/gram * °C * (36.6 °C - 22.7 °C) = 2043.7 calories.
Therefore, the water absorbed 2043.7 calories of heat.
Learn more about Heat Transfer here:
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