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Answer :
Final answer:
The Young's Modulus for the rope is approximately 3.52 × 10^9 N/m^2.
Explanation:
To calculate Young's Modulus for the rope, we need to use the formula:
E = (F/A) / (ΔL/L)
First, let's calculate the force applied to the rope. The weight of the mountain climber can be calculated using the formula:
Weight = mass × acceleration due to gravity
Weight = 84 kg × 9.8 m/s^2 = 823.2 N
Next, let's calculate the cross-sectional area of the rope. The formula for the area of a circle is:
A = πr^2
Given that the diameter of the rope is 1.0 cm, the radius can be calculated as:
Radius = diameter / 2 = 1.0 cm / 2 = 0.5 cm = 0.005 m
Now we can calculate the area:
A = π(0.005 m)^2 = 7.85 × 10^-5 m^2
Next, let's calculate the change in length of the rope. The original length of the rope is 37.4 m and it stretches by 26 cm, so the change in length is:
ΔL = 26 cm = 0.26 m
Finally, we can plug these values into the formula for Young's Modulus:
E = (823.2 N / 7.85 × 10^-5 m^2) / (0.26 m / 37.4 m)
Calculating this expression gives us:
E ≈ 3.52 × 10^9 N/m^2
Learn more about young's modulus here:
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