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Using the equation

\[ EER = [662 - (9.53 \times \text{age in years})] + PA \times [(15.91 \times \text{weight in kg}) + (539.6 \times \text{height in m})] \]

estimate the energy requirements for a sedentary, 30-year-old man who weighs 182 lb and is 6'0" tall.

Answer :

Final answer:

The estimated energy requirement for a sedentary, 30-year-old man weighing 182 lb and measuring 6'0" tall is approximately 2678 kcal/day, using the provided EER equation and factoring in his age, weight, and height, with a PA coefficient of 1.0 for sedentary activity.

Explanation:

To estimate the energy requirements for a sedentary, 30-year-old man who is 182 lb (which is approximately 82.6 kg) and 6'0" tall (which is approximately 1.83 m), we can use the provided Estimated Energy Requirement (EER) equation:

EER = [662 - (9.53 × age years)] + PA × [(15.91 × wt kg) + (539.6 × ht m)].

For a sedentary man, the Physical Activity (PA) coefficient is typically around 1.0. Therefore, substituting the values into the equation:

EER = [662 - (9.53 × 30)] + 1.0 × [(15.91 × 82.6) + (539.6 × 1.83)].

First, calculate the age-related deduction:

662 - 285.9 = 376.1.

Then, compute the contribution of weight and height in the equation:

(15.91 × 82.6) + (539.6 × 1.83) = 1314.306 + 987.488 = 2301.794.

Now, apply the Physical Activity factor:

1.0 × 2301.794 = 2301.794.

Finally, add this to the earlier calculation:

EER = 376.1 + 2301.794 = 2677.894 kcal/day.

This value rounds to nearly 2678 kcal/day, which is the estimated energy requirement for this individual.

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