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How many total moles of ions are released when the following samples dissolve completely in water? Ensure that each of your answer entries has the correct number of significant figures.

**Part 1 of 2:**
66.9 g of [tex]Ba(OH)_2 \cdot 8H_2O[/tex] = _____ mol

**Part 2 of 2:**
[tex]6.89 \times 10^{-1}[/tex] g of [tex]NiBr_2 \cdot 3H_2O[/tex] = _____ mol

Answer :

Final answer:

The total moles of ions released are 0.212 mol for Ba(OH)2 · 8H2O and 2.91 × 10^(-3) mol for NiBr2 · 3H2O.

Explanation:

Part 1: To calculate the number of moles of Ba(OH)2 · 8H2O, we need to divide the given mass by the molar mass. The molar mass of Ba(OH)2 · 8H2O is 315.46 g/mol. Therefore, the number of moles is 66.9 g / 315.46 g/mol = 0.212 mol.

Part 2: To calculate the number of moles of NiBr2 · 3H2O, we divide the given mass by the molar mass. The molar mass of NiBr2 · 3H2O is 236.51 g/mol. Therefore, the number of moles is 6.89 × 10^(-1) g / 236.51 g/mol = 2.91 × 10^(-3) mol.

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