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Calculate the change in internal energy for a system that is giving off 35.8 kJ of heat and is expanding from 8 L to 16 L under a pressure of 2 atm.

Answer :

The change in internal energy for the system is -19.8 kJ.

To calculate the change in internal energy (ΔU) for the system, we need to consider the heat transferred (q) and the work done (w) by the system.

q = -35.8 kJ (negative value indicates heat being given off by the system)

ΔV = 16 L - 8 L = 8 L (change in volume)

P = 2 atm (constant pressure)

To calculate the work done (w), we can use the equation w = -PΔV, where P is the pressure and ΔV is the change in volume. Substituting the given values, we have:

w = -(2 atm)(8 L) = -16 L·atm

The change in internal energy (ΔU) is calculated using the equation ΔU = q - w. Substituting the given values:

ΔU = (-35.8 kJ) - (-16 L·atm) = -35.8 kJ + 16 L·atm

Now we can calculate the change in internal energy:

ΔU = -35.8 kJ + 16 L·atm = -19.8 kJ

Therefore, the change in internal energy for the system is -19.8 kJ. The negative sign indicates that the internal energy of the system has decreased as it gave off heat and did work in expanding against the constant pressure.

To know more about internal energy refer here:

https://brainly.com/question/28333978#

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