Find the potential energy in electron-volts of a singly charged hydrogen atom, helium atom, nitrogen atom, and uranium atom near a generator dome charged to a positive 5 million volts.

The potential energy in electron-volts of a singly charged hydrogen, helium, nitrogen, and uranium atom near a generator dome charged to a positive 5 million volts can be calculated by multiplying the charge of the atom by the potential difference. For a hydrogen atom, the potential energy is 5,000,000 eV, for a helium atom it is 10,000,000 eV, for a nitrogen atom it is 25,000,000 eV, and for a uranium atom it is 460,000,000 eV.

Explanation:

The potential energy in electron-volts of a charged particle is calculated by multiplying the potential difference in volts by the charge of the particle in electron-volts. The charge of a hydrogen ion is +1 elementary charge and that of a helium ion is +2 elementary charges. The charge of a nitrogen ion is +5 elementary charges and that of a uranium ion is +92 elementary charges. By multiplying these charges by the given potential difference of +5 million volts, we can determine the potential energy in electron-volts for each atom.

For a singly charged hydrogen atom: Potential energy = (charge of hydrogen atom in electron-volts) * (potential difference in volts) = (1 eV) * (5,000,000 volts) = 5,000,000 eV

For a singly charged helium atom: Potential energy = (charge of helium atom in electron-volts) * (potential difference in volts) = (2 eV) * (5,000,000 volts) = 10,000,000 eV

For a singly charged nitrogen atom: Potential energy = (charge of nitrogen atom in electron-volts) * (potential difference in volts) = (5 eV) * (5,000,000 volts) = 25,000,000 eV

For a singly charged uranium atom: Potential energy = (charge of uranium atom in electron-volts) * (potential difference in volts) = (92 eV) * (5,000,000 volts) = 460,000,000 eV

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