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The national average for IQ scores is 100, and the standard deviation is 15. The distribution of IQ scores is bell-shaped. What percentage of students have an IQ score less than 92?

Answer :

Final answer:

Approximately 29.50% of students have an IQ score less than 92.

Explanation:

To find the percentage of students with an IQ score less than 92, we can use the normal distribution and the z-score formula.

The z-score measures how many standard deviations a particular value is from the mean.

First, we need to convert the IQ score of 92 to a z-score.

The formula is: z = (x - µ) / σ { where x is the given value, µ is the mean, and σ is the standard deviation }.

In this case, x = 92, µ = 100, and σ = 15.

Plugging in the values, we get:

z = (92 - 100) / 15 = -0.5333

Using a z-table or calculator, we can find the area under the curve to the left of z = -0.5333.

This gives us the percentage of students with an IQ score less than 92.

According to the z-table, the area to the left of z = -0.5333 is approximately 0.2950.

Therefore, approximately 29.50% of students have an IQ score less than 92.

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