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Answer :
Final answer:
In an uncharged Lead-208 atom, there are 82 protons, 126 neutrons, and 82 electrons, making option (a) the correct answer.
Explanation:
The atom in question is Lead-208 (Pb-208). For Lead-208, the number of protons is equal to the atomic number of lead, which is 82. To find the number of neutrons, we subtract the number of protons from the mass number (208 - 82), resulting in 126 neutrons. When the atom is uncharged, the number of electrons is equal to the number of protons, which is 82. Therefore, the correct answer is (a) Protons = 82, Neutrons = 126, Electrons = 82.
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