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A living cell with a tonicity (solute concentration) equivalent to 0.9% NaCl is placed in a solution containing 2% NaCl. Assume that aquaporins are present, and the membrane is permeable to water.

Answer :

Final answer:

A cell with 0.9% NaCl placed in a 2% NaCl solution experiences a hypertonic environment, causing it to lose water and shrink due to osmosis.

Explanation:

When a living cell with an internal tonicity equivalent to 0.9% NaCl is placed in a solution containing 2% NaCl, the surrounding solution is considered hypertonic. This is because the extracellular solution has a higher solute (salt) concentration than the cell's cytoplasm. The process of osmosis will cause water to move from the cell, which has a higher water potential, to the outside solution, where the water potential is lower because it has a higher solute concentration. Over time, this will result in the cell shrinking or losing water.

Osmolarity and tonicity are important concepts in understanding how cells interact with their environment. Isotonic conditions mean that the concentration of solutes is equal inside and outside the cell, resulting in no net water movement. Aquaporins, which are channel proteins in the cell membrane, facilitate the rapid movement of water across the cell membrane in response to these tonicity conditions.

Living organisms have developed strategies to maintain osmotic balance, such as the secretion of salts or the regulation of solute concentrations within their cells, to prevent cellular damage from excessive swelling or shrinking in hypo- or hypertonic environments.

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Rewritten by : Barada

Answer:

This question is incomplete

Explanation:

This illustration refers to an hypertonic solution. Hypertonic solution is a solution in which the surrounding solution has a higher solute concentration (2% of NaCl) than the cell's cytosol (0.9% of NaCl). In hypertonic solution, the solution outside the cell (with higher concentration) pulls the water from the cell's cytosol (via osmosis) causing the cell to shrink.