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Answer :
The final concentration of the KMnO₄ solution, after combining a 37.2 mL of 1.69 M solution with a 16.10 mL of 0.891 M solution, is approximately 1.448 M.
The subject of this question is in the field of Chemistry, specifically dealing with the concept of molar concentration or molarity. The question is about calculating the final concentration of a solution after mixing two solutions of different concentrations.
The number of moles of KMnO₄ in the first solution can be calculated by multiplying its volume by its molarity: 37.2 mL x 1.69 M = 62.868 mmol.
The number of moles in the second solution can be calculated in a similar manner: 16.10 mL x 0.891 M = 14.3371 mmol.
The total amount of moles in the mixed solution is therefore 62.868 mmol + 14.3371 mmol = 77.2051 mmol.
The total volume of the final solution is the sum of the two initial volumes: 37.2 mL + 16.10 mL = 53.3 mL.
The final concentration (C_f) of KMnO₄ can be calculated by dividing the total number of moles by the total volume: C_f = 77.2051 mmol / 53.3 mL = 1.448 M.
Therefore, the concentration of the final solution is approximately 1.448 M.
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