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Factor completely: [tex]27x^2 - 48y^2[/tex]

Answer :

To factor the expression [tex]\(27x^2 - 48y^2\)[/tex] completely, we can follow these steps:

1. Identify a Common Factor: First, observe if there's a greatest common factor (GCF) for the coefficients. Here, both 27 and 48 can be divided by 3. So, we can factor out 3 from the expression:

[tex]\[
27x^2 - 48y^2 = 3(9x^2 - 16y^2)
\][/tex]

2. Recognize a Difference of Squares: The expression [tex]\(9x^2 - 16y^2\)[/tex] is a difference of squares. The difference of squares formula is given by:

[tex]\[
a^2 - b^2 = (a - b)(a + b)
\][/tex]

Here, [tex]\(9x^2\)[/tex] is [tex]\((3x)^2\)[/tex] and [tex]\(16y^2\)[/tex] is [tex]\((4y)^2\)[/tex].

3. Apply the Difference of Squares Formula: Using the difference of squares formula, we factor [tex]\(9x^2 - 16y^2\)[/tex] as:

[tex]\[
9x^2 - 16y^2 = (3x - 4y)(3x + 4y)
\][/tex]

4. Write the Final Factorized Expression: Substitute the factored form back into the expression with the common factor we initially took out:

[tex]\[
27x^2 - 48y^2 = 3(3x - 4y)(3x + 4y)
\][/tex]

Therefore, the expression [tex]\(27x^2 - 48y^2\)[/tex] completely factorizes to [tex]\(3(3x - 4y)(3x + 4y)\)[/tex].

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