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Answer :
Final answer:
The balanced redox reaction is 3S(s) + 4NO3^-(aq) -> 3SO3 2^(aq) + 2NO(g) + 2NO2(g) + H2O(l), with S(s) as the reducing agent and NO3^- as the oxidizing agent. When applying the Rydberg formula to the calculation of the final quantum number in a hydrogen atom transition, we find that n = 2.
Explanation:
The first part of the question involves a redox reaction taking place in acidic conditions. The balanced equation is 3S(s) + 4NO3^-(aq) -> 3SO3 2^(aq) + 2NO(g) + 2NO2(g) + H2O(l). Here, S(s) is the reducing agent as it loses electrons and NO3^- is the oxidizing agent as it gains electrons.
Regarding the second part, it involves the calculation of the final value of n in the transition of an electron in a hydrogen atom. We would use the Rydberg formula, which is 1/λ = R(1/n1^2 - 1/n2^2). By rearranging and inputting the given data, we find that n2 = 2. Therefore, the final value of n in the transition is 2.
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