We appreciate your visit to given triangle KLM KL LM m. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer:
Step-by-step explanation:
Draw a really careful diagram of Circle with center O and ΔKLM Then make Draw line Segment LO Draw line Segment KO Mark the intersection point of LO and KM as C Since KL = LM the vertex is The diagonal LO bisects < KLM Therefore KM and LO intersect at right angles because ΔKCL and MCL are congruent making 2x = 180 x = 90 Now consider ΔKLO It isosceles because it is made up of 2 radii. That means that But OKC + OKL = 73 Now we are home free. We have the hypotenuse and an angle. We can find KC Cos(56) = KC/KO Cos(56) = KC/1.08 0.5592 * 1.08 = KC kc = 0.6039 KM = twice that amount which is 1.2079
Thanks for taking the time to read given triangle KLM KL LM m. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
Rewritten by : Barada
Answer:
Approximately 1.2078566715...
Step-by-step explanation:
Very tricky question! Because the picture doesn't seem to be drawn to scale...
With point O being the center of the circle, construct segments KO, LO, and MO, all of them are the radius of the circle, thus, equivalent.
Since KL=LM, then triangle KLM is an isosceles triangle and angle K is equal to angle M.
[tex]m (Yes that means "measure of angle") And because both angles K and M are 17 degrees, then angle L must be 146 degrees. Now, focus on triangle LOK, since KO=LO, triangle LOK is also an isosceles triangle, thus: [tex]m (Since half of angle L is 73) Then m After that, we can use the law of cosine to solve for KM: [tex](KM)^2=1.08^2+1.08^2-2(1.08)(1.08)Cos(68)\\(KM)^2=1.1664+1.1664-2.3328(0.37460659341...)\\(KM)^2=2.3328-0.87388226112...\\(KM)^2=1.45891773888...\\KM=1.2078566715...[/tex] The only thing that bothers me is angle KOM being 68 degrees because in the figure angle KOM is clearly an obtuse angle. I hope I am not tripping.
