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A certain mix of concrete is composed of 94 lb (one sack) of cement, 50 lb of water, 191 lb of sand, and 299 lb of gravel. The final mix of concrete will weigh 151.2 lb/ft³. How many sacks of cement will be needed for a wall with a volume of 1760 ft³?

Answer :

To calculate the number of sacks of cement needed for a wall with a volume of 1760 ft3, we need to determine the proportion of cement in the mix and then multiply it by the volume of the wall. We would need 4 sacks of cement for the wall.

To find the number of sacks of cement needed for a wall with a volume of 1760 ft3, we need to calculate the proportion of cement in the mix and then multiply it by the volume of the wall.

The proportion of cement in the mix is 94 lb per sack.

This represents 94/534 lb (sum of all materials in the mix).

The total amount of cement needed for the wall is therefore (94/534) * 1760 = 310.73 lb.

Since each sack is 94 lb, we would need 310.73/94 = 3.30 sacks of cement.

Rounding up, we would need 4 sacks of cement for the wall.

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