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A flywheel in the form of a heavy circular disk of diameter 0.821 m and mass 112 kg is mounted on a frictionless bearing. A motor connected to the flywheel accelerates it from rest to [tex]1270 \, \text{rev/min}[/tex]. What is the moment of inertia of the flywheel?

Answer :

Final answer:

The moment of inertia of the flywheel is calculated using the formula for a disk, resulting in an approximate value of 9.4 kg.m².

Explanation:

To find the moment of inertia of the flywheel, we first need to use the given dimensions and apply the formula for the moment of inertia of a disk, which is I = 0.5 * M * R2. Given the diameter of 0.821 m, the radius R would be half of that, 0.4105 m. The mass M of the flywheel is given as 112 kg. Substituting these values into the formula will give us the moment of inertia.

Calculating the Moment of Inertia:

  1. Find the radius (R): 0.821 m / 2 = 0.4105 m.
  2. Use the formula for the moment of inertia of a disk: I = 0.5 * M * R2.
  3. Substitute the given values: I = 0.5 * 112 kg * (0.4105 m)2 = 9.3945 kg.m2

The moment of inertia of the flywheel is therefore approximately 9.4 kg.m2.

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