High School

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Given the sequence:

[tex]-2 \frac{2}{3}, -5 \frac{1}{3}, -10 \frac{2}{3}, -21 \frac{1}{3}, -42 \frac{2}{3}, \cdots[/tex]

Which formula can be used to describe the sequence?

A. [tex]f(x+1)=-2 f(x)[/tex]

B. [tex]f(x+1)=-\frac{1}{2} f(x)[/tex]

C. [tex]f(x+1)=\frac{1}{2} f(x)[/tex]

D. [tex]f(x+1)=2 \pi(x)[/tex]

Answer :

To solve the problem of finding the formula that describes the given sequence, let's first look at the sequence provided:

[tex]\[
-2 \frac{2}{3}, -5 \frac{1}{3}, -10 \frac{2}{3}, -21 \frac{1}{3}, -42 \frac{2}{3}, \cdots
\][/tex]

This sequence seems to be decreasing with each term, and they can be expressed as improper fractions for easier comparison:

1. Convert the mixed numbers to improper fractions:
- [tex]\(-2 \frac{2}{3} = -\frac{8}{3}\)[/tex]
- [tex]\(-5 \frac{1}{3} = -\frac{16}{3}\)[/tex]
- [tex]\(-10 \frac{2}{3} = -\frac{32}{3}\)[/tex]
- [tex]\(-21 \frac{1}{3} = -\frac{64}{3}\)[/tex]
- [tex]\(-42 \frac{2}{3} = -\frac{128}{3}\)[/tex]

2. Observe how the sequence progresses:
- To find if there is a consistent multiplication factor between terms, divide each term by its predecessor:
- [tex]\(\frac{-16/3}{-8/3} = 2\)[/tex]
- [tex]\(\frac{-32/3}{-16/3} = 2\)[/tex]
- [tex]\(\frac{-64/3}{-32/3} = 2\)[/tex]
- [tex]\(\frac{-128/3}{-64/3} = 2\)[/tex]

3. Each term is obtained by multiplying the previous term by [tex]\(-2\)[/tex]. Therefore, there is a consistent pattern that each term becomes twice the previous term but in the negative direction. The rule for this sequence is:

[tex]\[
f(x+1) = -2 \cdot f(x)
\][/tex]

Thus, the formula that accurately describes this sequence is [tex]\(f(x+1) = -2 \cdot f(x)\)[/tex].

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