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Answer :
Sure! Let's factor the expression [tex]\(16x^2 - 169y^2\)[/tex]. This expression is a difference of squares. The difference of squares formula is:
[tex]\[ a^2 - b^2 = (a - b)(a + b) \][/tex]
Here, we need to identify [tex]\(a^2\)[/tex] and [tex]\(b^2\)[/tex] in our expression.
First, let's rewrite [tex]\(16x^2\)[/tex] and [tex]\(169y^2\)[/tex] as squares:
[tex]\[ 16x^2 = (4x)^2 \][/tex]
[tex]\[ 169y^2 = (13y)^2 \][/tex]
So our expression [tex]\(16x^2 - 169y^2\)[/tex] can be rewritten as:
[tex]\[ (4x)^2 - (13y)^2 \][/tex]
Now, apply the difference of squares formula where [tex]\(a = 4x\)[/tex] and [tex]\(b = 13y\)[/tex]:
[tex]\[ (4x)^2 - (13y)^2 = (4x - 13y)(4x + 13y) \][/tex]
Thus, the factored form of [tex]\(16x^2 - 169y^2\)[/tex] is:
[tex]\[ (4x - 13y)(4x + 13y) \][/tex]
[tex]\[ a^2 - b^2 = (a - b)(a + b) \][/tex]
Here, we need to identify [tex]\(a^2\)[/tex] and [tex]\(b^2\)[/tex] in our expression.
First, let's rewrite [tex]\(16x^2\)[/tex] and [tex]\(169y^2\)[/tex] as squares:
[tex]\[ 16x^2 = (4x)^2 \][/tex]
[tex]\[ 169y^2 = (13y)^2 \][/tex]
So our expression [tex]\(16x^2 - 169y^2\)[/tex] can be rewritten as:
[tex]\[ (4x)^2 - (13y)^2 \][/tex]
Now, apply the difference of squares formula where [tex]\(a = 4x\)[/tex] and [tex]\(b = 13y\)[/tex]:
[tex]\[ (4x)^2 - (13y)^2 = (4x - 13y)(4x + 13y) \][/tex]
Thus, the factored form of [tex]\(16x^2 - 169y^2\)[/tex] is:
[tex]\[ (4x - 13y)(4x + 13y) \][/tex]
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