Answer :

Final answer:

The molar mass of Ca(CH₃COO)₂ can be calculated by adding the masses of calcium, carbon, hydrogen, and oxygen, with the correct answer being approximately 158.2 g/mol. So, the correct option is 3) 158.2 g/mole

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Explanation:

To identify the molar mass of calcium acetate Ca(CH₃COO)₂, we need to calculate the total mass of all the atoms in one mole of the compound. This includes the mass of calcium (Ca), carbon (C), hydrogen (H), and oxygen (O).

Using the given atomic masses (Ca=40.0, C=12.0, H=1.0, O=16.0), we can compute the molar mass as follows:

Mass of Ca: 1 × 40.0 g/mol = 40.0 g/mol
  • Mass of C: 4 (from 2 acetate groups) × 12.0 g/mol = 48.0 g/mol
  • Mass of H: 6 (from 2 acetate groups) × 1.0 g/mol = 6.0 g/mol
  • Mass of O: 4 (from 2 acetate groups) × 16.0 g/mol = 64.0 g/mol

Adding these together gives a total molar mass for calcium acetate of:

40.0 g/mol (Ca) + 48.0 g/mol (C) + 6.0 g/mol (H) + 64.0 g/mol (O) = 158.0 g/mol.

The choices provided include 158.18 g/mol and 158.2 g/mol which are close to our calculated value, allowing for slight variations due to rounding of atomic masses. Therefore, the correct answer is 158.2 g/mol.

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