High School

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A 94 kg water skier is being pulled by a boat with a force of 238 N, causing the skier to accelerate at 1.6 m/s². What is the drag force on the skier?

Answer :

Final answer:

The drag force on the 94 kg water skier is 87.6 N, calculated using Newton's second law by subtracting the net force (due to the skier's acceleration) from the pulling force of the boat.

Explanation:

The student wishes to determine the drag force acting on a water skier of mass 94 kg who is being pulled by a boat with a force of 238 N and is accelerating at 1.6 m/s². To find the drag force, we can use Newton's second law, which states that the sum of the forces acting on an object is equal to the product of its mass and its acceleration (F = ma).

Let's first calculate the net force on the skier due to the pulling force of the boat and the opposing drag force. We assume no other forces are acting horizontally:

Net force (Fnet) = Pulling force (boat) - Drag force

Since the skier is accelerating, we know that:

Fnet = mass (m) × acceleration (a)

= 94 kg × 1.6 m/s²

= 150.4 N

Substituting the value of the pulling force:

238 N - Drag force = 150.4 N

Therefore, the drag force can be calculated as:

Drag force = 238 N - 150.4 N

= 87.6 N

This drag force is the frictional resistance the water exerts on the skier, opposing their forward motion.

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