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A 5.00 kg box on an elevator accelerates upward at 1.00 m/s².

What is the normal force on the box?

A. 49.0 N
B. 5.00 N
C. 44.0 N
D. 54.0 N

Answer :

Final answer:

The normal force on the box is 49.0 N.

Explanation:

To determine the normal force on the box, we need to calculate the net force acting on it. The net force is equal to the mass of the box multiplied by its acceleration. In this case, the mass of the box is 5.00 kg and the acceleration is 1.00 m/s^2.

Therefore, the net force is 5.00 kg x 1.00 m/s^2 = 5.00 N.

Since the box is accelerating upward, the normal force on the box must be equal in magnitude to the net force, but in the opposite direction.

So the normal force on the box is 49.0 N.

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