Answer :

Sure! Let's solve the problem step-by-step:

To determine how many moles of HCl are in 39.3 mL of a 1.50 M HCl solution, we can use the formula:

[tex]\[ \text{Moles of solute} = \text{Molarity} \times \text{Volume of solution (in liters)} \][/tex]

Here are the steps:

1. Convert the volume from milliliters (mL) to liters (L):

Since there are 1000 milliliters in a liter, we divide the volume in milliliters by 1000 to get the volume in liters.
[tex]\[
\text{Volume in liters} = \frac{39.3 \, \text{mL}}{1000} = 0.0393 \, \text{L}
\][/tex]

2. Use the given molarity of the HCl solution:

The molarity of the solution is given as 1.50 M (moles per liter).

3. Calculate the moles of HCl using the formula:

[tex]\[
\text{Moles of HCl} = \text{Molarity of HCl} \times \text{Volume of solution in liters}
\][/tex]
[tex]\[
\text{Moles of HCl} = 1.50 \, M \times 0.0393 \, L = 0.05895 \, \text{moles}
\][/tex]

So, there are approximately 0.05895 moles of HCl in 39.3 mL of a 1.50 M HCl solution.

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Rewritten by : Barada