High School

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Two sides of a parallelogram are 49 feet and 78 feet. The measure of the angle between these sides is 59º.

Find the area of the parallelogram to the nearest square foot.

Answer :

Answer:

[tex]A=3276\ ft^2[/tex]

Step-by-step explanation:

Given that,

The sides of a parallelogram are 49 feet and 78 feet. The measure of the angle between these sides is 59º.

We need to find the area of the parallelogram.

Using trigonometry,

[tex]\sin(59)=\dfrac{h}{49}\\\\h=\sin(59)\times 49\\\\h=42.00\ ft[/tex]

We know that,

Area = base (b) × height (h)

So,

[tex]A=78\times 42.00\\\\A=3276\ ft^2[/tex]

So, the area of the parallelogram is equal to [tex]3276\ ft^2[/tex].

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