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Answer :
Final answer:
The concentration of nitrate ions in a 6.00 M Sr(NO3)2 solution is 12.0 M, since there are two nitrate ions per formula unit of Sr(NO3)2.The correct option is C
Explanation:
The question asks about the concentration of nitrate ions in a 6.00 M solution of strontium nitrate, Sr(NO3)2. Strontium nitrate dissociates into one strontium ion and two nitrate ions in solution, thus for every formula unit of Sr(NO3)2 dissolved, two nitrate ions are produced.
To find the concentration of nitrate ions, you multiply the molarity of the Sr(NO3)2 by 2, because there are two nitrate ions for every molecule of Sr(NO3)2.
Therefore, the concentration of nitrate ions in a 6.00 M Sr(NO3)2 solution is 12.0 M,
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