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Answer :
The correct answer is 44.0 g/mol.
According to the ideal gas equation:
M = mRT/PV
Where:
M = Molar mass (g/mol)
m = Mass of gas sample (g) = 98.2 g
R = Universal gas constant = 0.08206 L atm K^-1 mol^-1
T = Temperature (K) = 273.15 K (STP)
P = Pressure (atm) = 1 atm (STP)
V = Volume (L) = 50.0 L
Substituting the values:
M = (98.2 g)(0.08206[tex]L atm K^-1 mol^-1[/tex])(273.15 K) / (1 atm)(50.0 L)
M = 44.0 g/mol
Therefore, the molar mass of a 98.2 g sample of gas that fills a 50.0 liter container at STP is b) 44.0 g/mol.
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