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Answer :
Let's solve the problem step-by-step involving the two runners, A and B.
Understand the question:
- Runner A runs at a speed of 12 km/h.
- Runner B runs at a speed of 10 km/h and has a 6-minute head start.
Convert head start time into hours:
[tex]\text{6 minutes} = \frac{6}{60} \text{ hours} = 0.1 \text{ hours}[/tex]Determine the distance Runner B covers in the head start:
- In 0.1 hours, Runner B will cover:
[tex]\text{Distance} = \text{Speed} \times \text{Time} = 10 \text{ km/h} \times 0.1 \text{ hours} = 1 \text{ km}[/tex]
- In 0.1 hours, Runner B will cover:
Calculate when Runner A catches up to Runner B:
Let [tex]t[/tex] be the time in hours after Runner A starts until they catch up.
In [tex]t[/tex] hours, Runner A covers:
[tex]12t[/tex]During the same [tex]t[/tex] hours, Runner B covers:
[tex]10t + 1[/tex] (since Runner B initially had a 1 km lead)Set the distances equal since they meet at the same point:
[tex]12t = 10t + 1[/tex]Solve for [tex]t[/tex]:
[tex]12t - 10t = 1[/tex]
[tex]2t = 1[/tex]
[tex]t = 0.5[/tex] hours
Convert [tex]t[/tex] from hours to minutes:
- [tex]0.5[/tex] hours is [tex]0.5 \times 60 = 30[/tex] minutes
Therefore, Runner A will catch up with Runner B 30 minutes after Runner A starts. Hence, the correct multiple choice option is C. 30 min.
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