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Two runners start from the same point and run in the same direction. Runner A runs at 12 km/h, and Runner B runs at 10 km/h. If Runner B gets a 6-minute head start, after how many minutes from Runner A's start will Runner A catch up?

A. 25 min
B. 28 min
C. 30 min
D. 32 min

Answer :

Let's solve the problem step-by-step involving the two runners, A and B.


  1. Understand the question:


    • Runner A runs at a speed of 12 km/h.

    • Runner B runs at a speed of 10 km/h and has a 6-minute head start.



  2. Convert head start time into hours:
    [tex]\text{6 minutes} = \frac{6}{60} \text{ hours} = 0.1 \text{ hours}[/tex]


  3. Determine the distance Runner B covers in the head start:


    • In 0.1 hours, Runner B will cover:
      [tex]\text{Distance} = \text{Speed} \times \text{Time} = 10 \text{ km/h} \times 0.1 \text{ hours} = 1 \text{ km}[/tex]



  4. Calculate when Runner A catches up to Runner B:


    • Let [tex]t[/tex] be the time in hours after Runner A starts until they catch up.


    • In [tex]t[/tex] hours, Runner A covers:
      [tex]12t[/tex]


    • During the same [tex]t[/tex] hours, Runner B covers:
      [tex]10t + 1[/tex] (since Runner B initially had a 1 km lead)


    • Set the distances equal since they meet at the same point:
      [tex]12t = 10t + 1[/tex]


    • Solve for [tex]t[/tex]:
      [tex]12t - 10t = 1[/tex]
      [tex]2t = 1[/tex]
      [tex]t = 0.5[/tex] hours




  5. Convert [tex]t[/tex] from hours to minutes:


    • [tex]0.5[/tex] hours is [tex]0.5 \times 60 = 30[/tex] minutes




Therefore, Runner A will catch up with Runner B 30 minutes after Runner A starts. Hence, the correct multiple choice option is C. 30 min.

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Rewritten by : Barada