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Calculate the molarity of a 7.04% by mass solution of H₂SO₄ in H₂O. The density of this solution is 1.048 g/mL and the molar mass of H₂SO₄ is 98.1 g/mol.

Answer :

A substance's molarity (M) is the volume of solution in which it is present.

The molarity of the solution is 0.747 or 7.47mol/l

How to find the molarity?

A substance's molarity (M) is the volume of solution in which it is present.

The amount of a solute in moles per liter of a solution is known as molarity.

Let the mass of solution m = 100g

7.04/100 * 100 = 7.04g

Therefore, the mass of H 2 SO 4 = 7.04g

Number of moles of H2SO4 = Mass of H2SO4 /Molar mass

The number of moles of H2SO4 = 7.04g/98.1g/mol

= 0.071 mol

The volume of solution = Mass of solution/Density of solution

V = 100g/1.048m/l

= 100g/1.048m/l * 1/1000ml/l

= 0.095l

Molarity = Moles of solute/Volume of solution (l)

Molarity = 0.071 mol/0.095l

= 0.747 or 7.47mol/l

To learn more about molarity, refer

https://brainly.com/question/14469428

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