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Answer :
Final answer:
The width of the rectangle is found to be 6 units and the length is 23 units. This problem can be solved using algebra by setting up an equation representing the given conditions.
Explanation:
This problem can be solved using algebra, specifically equations related to rectangles. Let's denote the width of the rectangle as x. The problem says that the length is eleven more than twice the width, so we can denote the length as 2x+11.
The perimeter of a rectangle is calculated as P = 2L + 2W, where L is the length and W is the width. We know that the perimeter is 58, therefore, substituting the given values we have 58 = 2(2x+11) + 2x.
Solving that equation leads to x = 6. Hence, the width of the rectangle is 6 units. The length, calculated as 2x+11, would then be 23 units.
Learn more about Rectangle Dimensions here:
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