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Answer :
The wavelength of the emitted photon corresponding to the hydrogen atom electron transiting from the second excited state to the ground state is 97.3 nm.
As per the question, the electron is moving from the second excited state (n = 3) to the ground state (n = 1), so n₁ = 3 and n₂ = 1.
Thus, λ = R[(1/1²) - (1/3²)] = R[(1/1) - (1/9)] = R(8/9) where R is the Rydberg constant = 1.097 x 10⁷/m.
λ = (1.097 x 10⁷/m) x (8/9) = 9.75 x 10⁵/m = 97.5 nm ≈ 97.3 nm (Correct to 2 decimal places).
Therefore, the answer is option C. 97.3 nm.
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