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Answer :
To solve the problem of finding the first number, let's go through the steps together:
We have two consecutive numbers, which we can represent as [tex]\( n \)[/tex] and [tex]\( n+1 \)[/tex].
The problem states that the sum of these two numbers is 157. We can create an equation to express this relationship:
[tex]\[ n + (n + 1) = 157 \][/tex]
Simplify the equation:
[tex]\[ 2n + 1 = 157 \][/tex]
Now, let's solve for [tex]\( n \)[/tex]:
1. Subtract 1 from both sides to isolate the term with [tex]\( n \)[/tex]:
[tex]\[ 2n = 157 - 1 \][/tex]
[tex]\[ 2n = 156 \][/tex]
2. Divide both sides by 2 to solve for [tex]\( n \)[/tex]:
[tex]\[ n = \frac{156}{2} \][/tex]
[tex]\[ n = 78 \][/tex]
So, the first number is 78. Therefore, the correct answer is:
B. 78
We have two consecutive numbers, which we can represent as [tex]\( n \)[/tex] and [tex]\( n+1 \)[/tex].
The problem states that the sum of these two numbers is 157. We can create an equation to express this relationship:
[tex]\[ n + (n + 1) = 157 \][/tex]
Simplify the equation:
[tex]\[ 2n + 1 = 157 \][/tex]
Now, let's solve for [tex]\( n \)[/tex]:
1. Subtract 1 from both sides to isolate the term with [tex]\( n \)[/tex]:
[tex]\[ 2n = 157 - 1 \][/tex]
[tex]\[ 2n = 156 \][/tex]
2. Divide both sides by 2 to solve for [tex]\( n \)[/tex]:
[tex]\[ n = \frac{156}{2} \][/tex]
[tex]\[ n = 78 \][/tex]
So, the first number is 78. Therefore, the correct answer is:
B. 78
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