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The orbital period of Saturn is 10,832.327 days. What is the orbital period in seconds?

A. 15,598,550 s
B. 935,913,050 s
C. 125 s
D. 38,996,377 s

Answer :

Final answer:

The orbital period of Saturn in seconds is calculated by multiplying its time in days (10,832.327) by the number of hours in a day (24), minutes in an hour (60), and seconds in a minute (60), yielding approximately 935,913,050 seconds. Hence, option B is the correct answer.

Explanation:

The orbital period of Saturn, as given, is 10,832.327 days. To convert this number into seconds, you would use the fact that there are 24 hours in a day, 60 minutes in an hour, and 60 seconds in a minute. Thus, the conversion would look like this:

10,832.327 days * 24 hours/day * 60 minutes/hour * 60 seconds/minute = 935,913,050 seconds

This means that option B, 935,913,050 seconds, is the correct orbital period of Saturn in seconds. This calculation is a part of the subject of Physics, particularly when studying planetary motions and Kepler's laws.

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