We appreciate your visit to How many grams of silver are in 187 g of tex Ag 2S tex. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
There are approximately 144.88 grams of silver in 187 grams of Ag2S.To determine the amount of silver (Ag) present in 187g of Ag2S, we need to consider the molar mass and stoichiometry of the compound.
The molar mass of Ag2S can be calculated as follows:
Ag: 1 atom x 107.87 g/mol = 107.87 g/mol
S: 1 atom x 32.07 g/mol = 32.07 g/mol
Total: 107.87 g/mol + 32.07 g/mol = 139.94 g/mol
The molar mass of Ag2S is 139.94 g/mol, indicating that 1 mole of Ag2S weighs 139.94 grams.
To determine the amount of Ag in 187g of Ag2S, we can set up a proportion:
(187 g Ag2S) / (139.94 g Ag2S) = (x g Ag) / (107.87 g Ag)
Solving this proportion, we find:
x g Ag = (187 g Ag2S) * (107.87 g Ag) / (139.94 g Ag2S) = 144.88 g Ag
For more such questions on silver
https://brainly.com/question/28823833
#SPJ11
Thanks for taking the time to read How many grams of silver are in 187 g of tex Ag 2S tex. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada