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A 2-m\(^3\) tank holds a two-phase liquid–vapor mixture of carbon dioxide at -17ºC. The quality of the mixture is 40.0%.

For saturated carbon dioxide at -17ºC:
- \(v_f = 0.9827 \times 10^{-3} \, \text{m}^3/\text{kg}\)
- \(v_g = 1.756 \times 10^{-3} \, \text{m}^3/\text{kg}\)

Determine the masses of saturated liquid and saturated vapor, each in kg.

What is the percent of the total volume occupied by saturated liquid?

Answer :

To determine the Mass calculation of saturated liquid and saturated vapor in a tank, we use the specific volumes of the liquid and vapor phases at -17ºC. The mass of the liquid is 2035.5 kg and the mass of the vapor is 1139.3 kg. The percent of the total volume occupied by the saturated liquid is 0.0982%.

To determine the masses of saturated liquid and saturated vapor, we need to first find the specific volumes of the liquid and vapor phases at -17ºC.

The specific volumes are given as 0.9827 x 10-3 m3/kg for the liquid and 1.756 x 10-3 m3/kg for the vapor.

We can calculate the mass of the saturated liquid by using the formula m = V/v, where m is the mass of the liquid, V is the volume of the tank, and v is the specific volume of the liquid.

Substituting the given values, we have m = 2/0.9827 x 10-3 = 2035.5 kg.

Similarly, we can calculate the mass of the saturated vapor using the same formula. The mass of the vapor is m = 2/1.756 x 10-3 = 1139.3 kg.

To find the percent of the total volume occupied by the saturated liquid, we use the formula Volume percent = (Vliquid/Vtotal) x 100%. Substituting the values, we have Volume percent = (2/2035.5) x 100% = 0.0982%.

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