We appreciate your visit to A 50 kg student climbs 5 m up a rope What is the work done against gravity a 50 J b 245 J c 500. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The work done against gravity for a 50 kg student climbing 5 m up a rope is 2450 joules, calculated using the formula W = m imes g imes h, and the correct answer is d) 2450 J.
Explanation:
To calculate the work done against gravity when the student climbs up a rope, we can use the formula Work (W) = force (F) times distance (d). Here, the force applied is equivalent to the weight of the student, which is the product of the student's mass (m) and the acceleration due to gravity (g), typically 9.8 m/s2. The distance is the height (h) the student climbs. Therefore, the work done against gravity is W = m times g times h.
For a 50 kg student climbing 5 meters up:
- Mass (m) = 50 kg
- Acceleration due to gravity (g) = 9.8 m/s2
- Height (h) = 5 m
Plugging in the values, we get:
W = 50 kg times 9.8 m/s2 times 5 m = 2450 J
The work done against gravity is 2450 joules, so the correct answer is d) 2450 J.
Thanks for taking the time to read A 50 kg student climbs 5 m up a rope What is the work done against gravity a 50 J b 245 J c 500. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
