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Answer :
To identify the compounds involved in the neutralization reaction, let's break down the equation:
[tex]\[ \text{Sr(OH)}_2 + 2 \text{HNO}_3 \rightarrow \text{Sr(NO}_3\text{)}_2 + 2 \text{H}_2\text{O} \][/tex]
1. Identify the Acid:
- Acids are substances that release hydrogen ions ([tex]\(\text{H}^+\)[/tex]) in a solution. In this reaction, [tex]\(\text{HNO}_3\)[/tex] (Nitric acid) is the acid because it donates hydrogen ions.
2. Identify the Base:
- Bases are substances that release hydroxide ions ([tex]\(\text{OH}^-\)[/tex]) in a solution. Here, [tex]\(\text{Sr(OH)}_2\)[/tex] (Strontium hydroxide) is the base as it provides hydroxide ions.
3. Identify the Salt:
- A salt is formed from the cation of the base and the anion of the acid. In this reaction, [tex]\(\text{Sr(NO}_3\text{)}_2\)[/tex] (Strontium nitrate) is the salt, created by combining the strontium ion ([tex]\(\text{Sr}^{2+}\)[/tex]) with the nitrate ion ([tex]\(\text{NO}_3^-\)[/tex]).
4. Identify the Water:
- Water ([tex]\(\text{H}_2\text{O}\)[/tex]) is a common product of neutralization reactions and is formed when hydrogen ions from the acid combine with hydroxide ions from the base.
Now arrange the labels to the corresponding compounds in the reaction:
- Base: [tex]\(\text{Sr(OH)}_2\)[/tex]
- Acid: [tex]\(\text{HNO}_3\)[/tex]
- Salt: [tex]\(\text{Sr(NO}_3\text{)}_2\)[/tex]
- Water: [tex]\(\text{H}_2\text{O}\)[/tex]
This breakdown helps identify all components involved in the neutralization reaction.
[tex]\[ \text{Sr(OH)}_2 + 2 \text{HNO}_3 \rightarrow \text{Sr(NO}_3\text{)}_2 + 2 \text{H}_2\text{O} \][/tex]
1. Identify the Acid:
- Acids are substances that release hydrogen ions ([tex]\(\text{H}^+\)[/tex]) in a solution. In this reaction, [tex]\(\text{HNO}_3\)[/tex] (Nitric acid) is the acid because it donates hydrogen ions.
2. Identify the Base:
- Bases are substances that release hydroxide ions ([tex]\(\text{OH}^-\)[/tex]) in a solution. Here, [tex]\(\text{Sr(OH)}_2\)[/tex] (Strontium hydroxide) is the base as it provides hydroxide ions.
3. Identify the Salt:
- A salt is formed from the cation of the base and the anion of the acid. In this reaction, [tex]\(\text{Sr(NO}_3\text{)}_2\)[/tex] (Strontium nitrate) is the salt, created by combining the strontium ion ([tex]\(\text{Sr}^{2+}\)[/tex]) with the nitrate ion ([tex]\(\text{NO}_3^-\)[/tex]).
4. Identify the Water:
- Water ([tex]\(\text{H}_2\text{O}\)[/tex]) is a common product of neutralization reactions and is formed when hydrogen ions from the acid combine with hydroxide ions from the base.
Now arrange the labels to the corresponding compounds in the reaction:
- Base: [tex]\(\text{Sr(OH)}_2\)[/tex]
- Acid: [tex]\(\text{HNO}_3\)[/tex]
- Salt: [tex]\(\text{Sr(NO}_3\text{)}_2\)[/tex]
- Water: [tex]\(\text{H}_2\text{O}\)[/tex]
This breakdown helps identify all components involved in the neutralization reaction.
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