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What is the kinetic energy of a proton that is traveling at a speed of 3125 m/s?

(Note: Use the formula \( K = \frac{1}{2}mv^2 \), where \( m \) is the mass of the proton and \( v \) is its velocity.)

Answer :

Final answer:

The kinetic energy of a proton traveling at a speed of 3125 m/s is approximately 8.15 * 10^-20 Joules, calculated using the kinetic energy formula: KE = 0.5 * m * v².

Explanation:

The kinetic energy of an object can be calculated using the equation KE = 0.5 * m * v², where m is the mass and v is the speed. For a proton, the mass is approximately 1.67 * 10^-27 kg. So if we substitute these values into the equation, we get KE = 0.5 * (1.67 * 10^-27 kg) * (3125 m/s)². After calculating this, we find that the kinetic energy of the proton is approximately 8.15 * 10^-20 Joules.

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