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Answer :
Final answer:
The kinetic energy of a proton traveling at a speed of 3125 m/s is approximately 8.15 * 10^-20 Joules, calculated using the kinetic energy formula: KE = 0.5 * m * v².
Explanation:
The kinetic energy of an object can be calculated using the equation KE = 0.5 * m * v², where m is the mass and v is the speed. For a proton, the mass is approximately 1.67 * 10^-27 kg. So if we substitute these values into the equation, we get KE = 0.5 * (1.67 * 10^-27 kg) * (3125 m/s)². After calculating this, we find that the kinetic energy of the proton is approximately 8.15 * 10^-20 Joules.
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