High School

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69. Find the simple interest when the principal is ₹2000, the rate of interest is 8% per annum, and the time is 3 years.

(a) ₹480
(b) ₹450
(c) ₹400
(d) ₹460

70. A car travels 240 Km in 4 hours. What is the speed of the car?

(a) 40 Km/hr
(b) 60 Km/hr
(c) 80 Km/hr
(d) 100 Km/hr

71. What is the perimeter of a rectangle when the length is 12 cm and the breadth is 8 cm?

(a) 40 cm
(b) 44 cm
(c) 48 cm
(d) None of these

72. Find the perimeter of a triangle with sides of 4 ft, 3 ft, and 2 ft.

(a) 9 ft 11 inches
(b) 10 ft
(c) 9 ft
(d) 12 ft 2 inches

73. The population of a village was 375,070 in 1991. In 2001, it was found to have increased by 68,670. What was the population of the village in 2001?

(a) 443,740
(b) 403,740
(c) 443,070
(d) 433,740

74. If 12 men can complete a task in 15 days, how many men are required to complete the task in 10 days?

(a) 18
(b) 16
(c) 20
(d) 17

75. Find the value of 2 + 3 × 4 - 6 + 3.

(a) 10
(b) 12
(c) 14
(d) 11

**SECTION III: ELEMENTARY SCIENCE**

76. Fungi are plants that lack...?

(a) Oxygen
(b) Carbon dioxide
(c) Chlorophyll
(d) None of these

77. Which of the following is an air-borne disease?

(a) Pink eye
(b) Typhoid
(c) Measles
(d) None of the above

Answer :

Let's answer each of the questions one by one:

69. Simple Interest Calculation:

Simple Interest is calculated using the formula:
[tex]\text{Simple Interest (SI)} = \frac{\text{Principal} \times \text{Rate} \times \text{Time}}{100}[/tex]

Given:

  • Principal (P) = ₹2000
  • Rate (R) = 8% per annum
  • Time (T) = 3 years

Substituting these values into the formula:
[tex]\text{SI} = \frac{2000 \times 8 \times 3}{100} = 480[/tex]

Therefore, the simple interest is ₹480.

70. Speed of the Car:

Speed is calculated using the formula:
[tex]\text{Speed} = \frac{\text{Distance}}{\text{Time}}[/tex]

Given:

  • Distance = 240 Km
  • Time = 4 hours

So, the speed of the car is:
[tex]\text{Speed} = \frac{240}{4} = 60 \text{ Km/hr}[/tex]

Therefore, the speed of the car is 60 Km/hr.

71. Perimeter of a Rectangle:

The perimeter of a rectangle is calculated using the formula:
[tex]\text{Perimeter} = 2 \times (\text{Length} + \text{Breadth})[/tex]

Given:

  • Length = 12 cm
  • Breadth = 8 cm

Substituting these values into the formula:
[tex]\text{Perimeter} = 2 \times (12 + 8) = 2 \times 20 = 40 \text{ cm}[/tex]

Therefore, the perimeter of the rectangle is 40 cm.

72. Perimeter of a Triangle:

The perimeter of a triangle is the sum of the lengths of its sides:
[tex]\text{Perimeter} = \text{Side 1} + \text{Side 2} + \text{Side 3}[/tex]

Given sides:

  • 4 ft
  • 3 ft
  • 2 ft

Adding these values:
[tex]\text{Perimeter} = 4 + 3 + 2 = 9 \text{ feet}[/tex]

Therefore, the perimeter of the triangle is 9 feet.

73. Population of a Village in 2001:

The population in 2001 is the initial population plus the increase:
[tex]\text{Population in 2001} = \text{Initial Population} + \text{Increase}[/tex]

Given:

  • Initial Population = 375070
  • Increase = 68670

Adding these:
[tex]\text{Population in 2001} = 375070 + 68670 = 443740[/tex]

Therefore, the population in 2001 was 443740.

74. Number of Men Required:

This is an inverse proportion problem. Let the required number of men be [tex]x[/tex]. Using the formula for inverse proportion:
[tex]12 \times 15 = x \times 10[/tex]

Solving for [tex]x[/tex]:
[tex]x = \frac{12 \times 15}{10} = 18[/tex]

So, 18 men are required to complete the task in 10 days.

75. Evaluation of Expression:

Using the order of operations (BODMAS/BIDMAS):
[tex]2 + 3 \times 4 - 6 + 3[/tex]

First, multiply:
[tex]= 2 + 12 - 6 + 3[/tex]

Now, perform the additions and subtraction from left to right:
[tex]= 14 - 6 + 3 = 8 + 3 = 11[/tex]

Therefore, the value of the expression is 11.

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