High School

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Karissa begins to solve the equation [tex]\frac{1}{2}(x-14)+11=\frac{1}{2} x-(x-4)[/tex]. Her work is correct and is shown below.

[tex]
\begin{array}{c}
\frac{1}{2}(x-14)+11=\frac{1}{2} x-(x-4) \\
\frac{1}{2} x-7+11=\frac{1}{2} x-x+4 \\
\frac{1}{2} x+4=-\frac{1}{2} x+4
\end{array}
[/tex]

When she subtracts 4 from both sides, [tex]\frac{1}{2} x=-\frac{1}{2} x[/tex] results. What is the value of [tex]x[/tex]?

A. -1
B. [tex]\frac{1}{2}[/tex]
C. 0
D. [tex]\frac{1}{2}[/tex]

Answer :

Sure, let's solve the equation step-by-step.

We begin with the equation:

[tex]\[
\frac{1}{2}(x-14) + 11 = \frac{1}{2} x - (x - 4)
\][/tex]

First, distribute the [tex]\(\frac{1}{2}\)[/tex] on the left side:

[tex]\[
\frac{1}{2} x - \frac{1}{2} \cdot 14 + 11 = \frac{1}{2} x - (x - 4)
\][/tex]

Simplify the left side:

[tex]\[
\frac{1}{2} x - 7 + 11 = \frac{1}{2} x - x + 4
\][/tex]

Combine like terms on the left side:

[tex]\[
\frac{1}{2} x + 4 = \frac{1}{2} x - x + 4
\][/tex]

Now, simplify the right side. Subtract [tex]\(\frac{1}{2} x\)[/tex] and add 4 on the right side:

[tex]\[
\frac{1}{2} x + 4 = -\frac{1}{2} x + 4
\][/tex]

Next, subtract 4 from both sides to eliminate the constant term:

[tex]\[
\frac{1}{2} x = -\frac{1}{2} x
\][/tex]

Now, let's add [tex]\(\frac{1}{2} x\)[/tex] to both sides to combine the [tex]\(x\)[/tex] terms on one side:

[tex]\[
\frac{1}{2} x + \frac{1}{2} x = 0
\][/tex]

This results in:

[tex]\[
x = 0
\][/tex]

So, the value of [tex]\(x\)[/tex] is [tex]\(0\)[/tex].

Thanks for taking the time to read Karissa begins to solve the equation tex frac 1 2 x 14 11 frac 1 2 x x 4 tex Her work is correct and. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

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