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Answer :
To solve the problem of finding the Highest Common Factor (HCF) using different methods, let's go through each step and approach:
Finding HCF by Listing Common Factors:
a. 14 and 16:
List the factors of each number:
Factors of 14: [tex]1, 2, 7, 14[/tex]
Factors of 16: [tex]1, 2, 4, 8, 16[/tex]
Common factors: [tex]1, 2[/tex]
The HCF is the largest common factor: [tex]\boxed{2}[/tex]
b. 27 and 35:
Factors of 27: [tex]1, 3, 9, 27[/tex]
Factors of 35: [tex]1, 5, 7, 35[/tex]
Common factor: [tex]1[/tex]
The HCF is: [tex]\boxed{1}[/tex]
c. 20 and 30:
Factors of 20: [tex]1, 2, 4, 5, 10, 20[/tex]
Factors of 30: [tex]1, 2, 3, 5, 6, 10, 15, 30[/tex]
Common factors: [tex]1, 2, 5, 10[/tex]
The HCF is: [tex]\boxed{10}[/tex]
d. 18, 52 and 64:
Factors of 18: [tex]1, 2, 3, 6, 9, 18[/tex]
Factors of 52: [tex]1, 2, 4, 13, 26, 52[/tex]
Factors of 64: [tex]1, 2, 4, 8, 16, 32, 64[/tex]
Common factors: [tex]1, 2[/tex]
The HCF is: [tex]\boxed{2}[/tex]
e. 40, 45 and 80:
Factors of 40: [tex]1, 2, 4, 5, 8, 10, 20, 40[/tex]
Factors of 45: [tex]1, 3, 5, 9, 15, 45[/tex]
Factors of 80: [tex]1, 2, 4, 5, 8, 10, 16, 20, 40, 80[/tex]
Common factors: [tex]1, 5[/tex]
The HCF is: [tex]\boxed{5}[/tex]
f. 12, 21 and 63:
Factors of 12: [tex]1, 2, 3, 4, 6, 12[/tex]
Factors of 21: [tex]1, 3, 7, 21[/tex]
Factors of 63: [tex]1, 3, 9, 21, 63[/tex]
Common factor: [tex]1, 3[/tex]
The HCF is: [tex]\boxed{3}[/tex]
Finding HCF Using Factorisation Method:
a. 52 and 70:
Prime factors of 52: [tex]2^2 \times 13[/tex]
Prime factors of 70: [tex]2 \times 5 \times 7[/tex]
Common prime factor: [tex]2[/tex]
The HCF is: [tex]\boxed{2}[/tex]
b. 144 and 290:
Prime factors of 144: [tex]2^4 \times 3^2[/tex]
Prime factors of 290: [tex]2 \times 5 \times 29[/tex]
Common prime factor: [tex]2[/tex]
The HCF is: [tex]\boxed{2}[/tex]
c. 10 and 85:
Prime factors of 10: [tex]2 \times 5[/tex]
Prime factors of 85: [tex]5 \times 17[/tex]
Common prime factor: [tex]5[/tex]
The HCF is: [tex]\boxed{5}[/tex]
d. 62 and 120:
Prime factors of 62: [tex]2 \times 31[/tex]
Prime factors of 120: [tex]2^3 \times 3 \times 5[/tex]
Common prime factor: [tex]2[/tex]
The HCF is: [tex]\boxed{2}[/tex]
e. 18, 54 and 72:
Prime factors of 18: [tex]2 \times 3^2[/tex]
Prime factors of 54: [tex]2 \times 3^3[/tex]
Prime factors of 72: [tex]2^3 \times 3^2[/tex]
Common prime factors: [tex]2 \times 3^2 = 18[/tex]
The HCF is: [tex]\boxed{18}[/tex]
f. 14, 56 and 70:
Prime factors of 14: [tex]2 \times 7[/tex]
Prime factors of 56: [tex]2^3 \times 7[/tex]
Prime factors of 70: [tex]2 \times 5 \times 7[/tex]
Common prime factors: [tex]2 \times 7 = 14[/tex]
The HCF is: [tex]\boxed{14}[/tex]
Finding HCF Using Division Method:
a. 28, 40:
- Divide 40 by 28, the remainder is 12.
- Divide 28 by 12, the remainder is 4.
- Divide 12 by 4, the remainder is 0.
The HCF is the divisor when remainder is 0: [tex]\boxed{4}[/tex]
b. 54, 96:
- Divide 96 by 54, the remainder is 42.
- Divide 54 by 42, the remainder is 12.
- Divide 42 by 12, the remainder is 6.
- Divide 12 by 6, the remainder is 0.
The HCF is: [tex]\boxed{6}[/tex]
c. 30, 84:
- Divide 84 by 30, the remainder is 24.
- Divide 30 by 24, the remainder is 6.
- Divide 24 by 6, the remainder is 0.
The HCF is: [tex]\boxed{6}[/tex]
d. 49, 63:
- Divide 63 by 49, the remainder is 14.
- Divide 49 by 14, the remainder is 7.
- Divide 14 by 7, the remainder is 0.
The HCF is: [tex]\boxed{7}[/tex]
e. 22, 66 and 88:
First find HCF of 22 and 66:
- Divide 66 by 22, the remainder is 0.
The HCF of 22 and 66 is: [tex]22[/tex]
Next, find HCF of 22 and 88:
- Divide 88 by 22, the remainder is 0.
The HCF of 22, 66, and 88 is: [tex]\boxed{22}[/tex]
f. 90, 120 and 160:
First find HCF of 90 and 120:
- Divide 120 by 90, the remainder is 30.
- Divide 90 by 30, the remainder is 0.
The HCF of 90 and 120 is: [tex]30[/tex]
Next, find HCF of 30 and 160:
- Divide 160 by 30, the remainder is 10.
- Divide 30 by 10, the remainder is 0.
The HCF of 90, 120, and 160 is: [tex]\boxed{10}[/tex]
By following these approaches, you can find the HCF of numbers using listing common factors, factorization, and division methods. Each method gives you the same result, ensuring the answers are correct.
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