High School

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Select the correct answer.

A restaurant has a total of 60 tables. Of those tables, 38 are round, and 13 are located by the window. There are 6 round tables by the window. If tables are randomly assigned to customers, what is the probability that a customer will be seated at a round table or by the window?

A. [tex]\frac{45}{60}[/tex]

B. [tex]\frac{41}{60}[/tex]

C. [tex]\frac{47}{60}[/tex]

D. [tex]\frac{29}{60}[/tex]

Answer :

To solve this problem, we want to determine the probability that a customer will be seated at a round table or a table by the window.

Let's define:
- Total tables = 60
- Round tables = 38
- Tables by the window = 13
- Round tables by the window = 6

We use the principle of inclusion-exclusion to calculate the number of tables that are either round or by the window. This helps us avoid double-counting those tables that are both round and by the window.

1. Start by adding the number of round tables and the number of tables by the window:
[tex]\[
38 \text{ (round tables)} + 13 \text{ (window tables)} = 51
\][/tex]

2. Subtract the number of tables that are double-counted (tables that are both round and by the window):
[tex]\[
51 - 6 = 45
\][/tex]

So, there are 45 tables that are either round, by the window, or both.

Now we calculate the probability:
- The probability is the ratio of the number of tables that are round or by the window to the total number of tables.

[tex]\[
\frac{45}{60} = 0.75
\][/tex]

Therefore, the probability that a customer will be seated at a round table or by the window is [tex]\(\frac{45}{60}\)[/tex].

So, the correct answer is:
A. [tex]\(\frac{45}{60}\)[/tex]

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