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A small air conditioner maintains a cooled space at [tex]20^\circ C[/tex] when the outside temperature is [tex]35^\circ C[/tex]. The air conditioner removes energy at the rate of [tex]2.5 \text{ kW}[/tex] from the cooled space, and its coefficient of performance (COP) is 5.

Find the rate of entropy production, in [tex]\text{kW/K}[/tex].

Answer :

Final answer:

The rate of entropy production is 0.167 kW/°C.

Explanation:

The rate of entropy production can be calculated using the formula:

Entropy Production = Rate of Energy Input / Temperature Difference

In this case, the rate of energy input is given as 2.5 kW and the temperature difference is 35°C - 20°C = 15°C.

Therefore, the rate of entropy production is 2.5 kW / 15°C = 0.167 kW/°C.

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