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Element [tex] X [/tex] decays radioactively with a half-life of 11 minutes. If there are 300 grams of Element [tex] X [/tex], how long, to the nearest tenth of a minute, would it take the element to decay to 80 grams?

Use the formula:

[tex] y = a(0.5)^{\frac{t}{11}} [/tex]

Answer :

To solve this problem, we're looking at the radioactive decay of an element with a known half-life. The half-life is the time required for a quantity to reduce to half its initial amount. Let's break down the steps to find out how long it would take for 300 grams of Element X to decay to 80 grams.

Step 1: Understand the formula

The formula for radioactive decay is:

[tex]\[ y = a \times (0.5)^{\frac{t}{\text{half-life}}} \][/tex]

Where:
- [tex]\( y \)[/tex] is the remaining amount of the substance.
- [tex]\( a \)[/tex] is the initial amount.
- [tex]\( t \)[/tex] is the time in minutes.
- The half-life is given as 11 minutes.

Step 2: Plug in the known values

We start with 300 grams and want to find the time for it to decay to 80 grams. Plug these values into the formula:

[tex]\[ 80 = 300 \times (0.5)^{\frac{t}{11}} \][/tex]

Step 3: Solve the equation for [tex]\( t \)[/tex]

To find [tex]\( t \)[/tex], follow these steps:

1. Divide both sides by 300:

[tex]\[ \frac{80}{300} = (0.5)^{\frac{t}{11}} \][/tex]

2. Simplify the fraction:

[tex]\[ \frac{80}{300} = \frac{4}{15} \][/tex]

3. Take the natural logarithm of both sides to solve for [tex]\( t \)[/tex]:

[tex]\[ \ln \left(\frac{4}{15}\right) = \frac{t}{11} \times \ln(0.5) \][/tex]

4. Rearrange to isolate [tex]\( t \)[/tex]:

[tex]\[ t = \frac{\ln \left(\frac{4}{15}\right)}{\ln(0.5)} \times 11 \][/tex]

Step 4: Solve for [tex]\( t \)[/tex]

After calculating the natural logarithms and performing the arithmetic:

[tex]\[ t \approx 21.0 \][/tex]

Conclusion:

To the nearest tenth of a minute, it would take approximately 21.0 minutes for 300 grams of Element X to decay to 80 grams.

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