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A 3.82 g piece of limestone contains 2.62 g of [tex] \text{CaCO}_3 [/tex].

Based on these results, what is the mass percentage of [tex] \text{CaCO}_3 [/tex] in the limestone?

Answer :

Considering the definition of percentage by mass, the mass percentage of CaCO₃ is 68.59%.

What is mass percentage

The percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.

In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:

[tex]mass percentage=\frac{mass of solute}{mass of solution}x100[/tex]

Mass percentage of CaCO₃

In this case, you know:

  • mass of CaCO₃: 2.62 grams
  • mass of limestone: 3.82 grams

Replacing in the definition of mass percentage:

[tex]mass percentage=\frac{2.62 grams}{3.82 grams}x100[/tex]

mass percentage= 68.59 %

Finally, the mass percentage of CaCO₃ is 68.59%.

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Rewritten by : Barada

To find the mass percentage of CaCO3 in limestone, divide the mass of CaCO3 by the total mass of the limestone sample and multiply by 100. In this case, the mass percentage of CaCO3 in the limestone sample is 68.59%.

The mass percentage of CaCO3 in limestone can be calculated by dividing the mass of CaCO3 by the total mass of the limestone sample and then multiplying by 100. In this case:

Mass percentage of CaCO3 = (Mass of CaCO3 / Total mass of limestone) x 100

Using the given values, Mass percentage of CaCO3 = (2.62 g / 3.82 g) x 100 = 68.59%