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A woman is pushing a 38.7 kg lawnmower, initially at rest, with a 68.7 N forward force against friction. The lawnmower speeds up to 1.44 m/s in 3.81 seconds. How much force does friction exert on the mower?

Options:
A. 21.2 N
B. 26.5 N
C. 32.8 N
D. 37.1 N

Answer :

Final answer:

To determine the force of friction exerted on the lawnmower, we can calculate its acceleration using the given data. Then, using Newton's second law, we can find the net force acting on the lawnmower. By subtracting the applied force from the net force, we can determine the force of friction.

Explanation:

To determine the force of friction exerted on the lawnmower, we need to first calculate its acceleration. We can use the equation of motion: Final velocity = Initial velocity + (acceleration * time). Rearranging the equation, we have acceleration = (Final velocity - Initial velocity) / time. Plugging in the given values, we get acceleration = (1.44 m/s - 0 m/s) / 3.81 s = 0.377 m/s².

Next, we can calculate the net force acting on the lawnmower using Newton's second law: net force = mass * acceleration. Plugging in the values, we get net force = 38.7 kg * 0.377 m/s² = 14.88 N.

Since the net force is the vector sum of the applied force and the force of friction, we can find the force of friction by subtracting the applied force from the net force. Thus, the force of friction = net force - applied force = 14.88 N - 68.7 N = -53.82 N.

However, since the question asks for the magnitude of the force of friction (which cannot be negative), we take the absolute value of the result. Therefore, the force of friction exerted on the lawnmower is approximately 53.82 N.

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