High School

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Multiply:

[tex]\left(x^4+1\right)\left(3x^2+9x+2\right)[/tex]

A. [tex]x^4+3x^2+9x+3[/tex]

B. [tex]3x^6+9x^5+2x^4+3x^2+9x+2[/tex]

C. [tex]3x^7+9x^6+2x^5[/tex]

D. [tex]3x^8+9x^4+2x^4+3x^2+9x+2[/tex]

Answer :

Answer:

B

Step-by-step explanation:

given

([tex]x^{4}[/tex] + 1 )(3x² + 9x + 2 )

Each term in the second factor is multiplied by each term in the first factor, that is

[tex]x^{4}[/tex] (3x² + 9x + 2 ) + 1(3x² + 9x + 2 ) ← distribute parenthesis

= 3[tex]x^{6}[/tex] + 9[tex]x^{5}[/tex] + 2[tex]x^{4}[/tex] + 3x² + 9x + 2

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Rewritten by : Barada

Let's solve the multiplication problem step-by-step:

We need to multiply the polynomials [tex]\((x^4 + 1)\)[/tex] and [tex]\((3x^2 + 9x + 2)\)[/tex].

### Step 1: Distribute each term in [tex]\((x^4 + 1)\)[/tex] with every term in [tex]\((3x^2 + 9x + 2)\)[/tex].

1. Multiply [tex]\(x^4\)[/tex] with each term in the second polynomial:
- [tex]\(x^4 \cdot 3x^2 = 3x^{6}\)[/tex]
- [tex]\(x^4 \cdot 9x = 9x^{5}\)[/tex]
- [tex]\(x^4 \cdot 2 = 2x^{4}\)[/tex]

2. Multiply [tex]\(1\)[/tex] with each term in the second polynomial:
- [tex]\(1 \cdot 3x^2 = 3x^{2}\)[/tex]
- [tex]\(1 \cdot 9x = 9x\)[/tex]
- [tex]\(1 \cdot 2 = 2\)[/tex]

### Step 2: Combine all these products.

The result is formed by adding all these products together:

[tex]\[ 3x^6 + 9x^5 + 2x^4 + 3x^2 + 9x + 2 \][/tex]

So, the expression [tex]\((x^4 + 1)(3x^2 + 9x + 2)\)[/tex] simplifies to:

[tex]\[ 3x^6 + 9x^5 + 2x^4 + 3x^2 + 9x + 2 \][/tex]

And that's the final result of multiplying the given polynomials.